What is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3 g/cm3?

The density of any substance can be calculated using the following rule:
density = mass / volume
Therefore,
mass = density x volume

First we need to standardize the units:
volume = 7.379 x 10^-4 m^3
density = 19.3 gm / cm^3 = 19300 kg / m^3

Now, we will substitute with these values in the above mentioned equation to calculate the mass:
mass = density x volume
= 19300 x 7.379 x 10^-4 = 14.24147 kg

Answer Link

ardni313 ardni313 · Answer 2 · 2019-08-27T05:54:54+02:00

The mass of a gold bar = 1.424 x 10⁴ gram

Further Explanation

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm³ or kg / m³

Density formula:

[tex]\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}[/tex]

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm³

Mass is one of the principal quantities, which is related to the matter in the object

The volume itself is a derivative of length with a standard unit of m³

Volume is the amount of how much space an object has

Known variable

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

Asked

the mass of a gold bar

Answer

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram

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Keywords: density, mass, volume, a gold bar