Respuesta :
Let the consecutive odd integers be x, x+2.
Given,
4x = 7(x + 2) -29
4x = 7x + 14 - 29
3x = 15
x = 5
Thus, the consecutive odd integers are 5 and 7.
Given,
4x = 7(x + 2) -29
4x = 7x + 14 - 29
3x = 15
x = 5
Thus, the consecutive odd integers are 5 and 7.
odd integers are 2 apart
so they are x and x+2
the first is x and the 2nd is x+2
4 times the first is 29 less than 7 times the 2nd
4x=-29+7(x+2)
solve
distribute
4x=-29+7x+14
4x=-15+7x
minus 7x both sides
-3x=-15
divide both sides by -3
x=5
x+2=7
the numbers are 5 and 7
so they are x and x+2
the first is x and the 2nd is x+2
4 times the first is 29 less than 7 times the 2nd
4x=-29+7(x+2)
solve
distribute
4x=-29+7x+14
4x=-15+7x
minus 7x both sides
-3x=-15
divide both sides by -3
x=5
x+2=7
the numbers are 5 and 7