Respuesta :

LeChatNoir
mCuSO4: 64+32+16+4 = 160 g/mol

6,02×10²³ ------- 160g
3,36×10²³ -------- X
X = (160×3,36×10²³)/6,02×10²³
X = 89,3 g

:•)
craigsbarbara

Answer:

89.02g

Explanation:

First you have to calculate how many grams weighs one mole of CuSO4.

Cu = 63.5g

S = 32g

O = 16 x 4 = 64g

1 mole CuSO4 = 159.5g

 

Then we have to know that 1 mole is [tex]6.022x10 ^{23}[/tex] molecules.

Now we calculate  :

[tex]159.5g=6.022x10^{23} molecules [/tex]

   [tex]x=3.36x10^{23} molecules[/tex]

[tex]\frac{3.36x10^{23} x 159.5}{6.022x10^{23}}=89.02g[/tex]