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1) Consider the reaction represented by the equation 2HI(g) →← H2(g) + I2(g). At a temperature of 520 °C, the equilibrium concentration of HI is 0.80 M, of H2 is 0.010 M, and of I2 is 0.010 M. What is the K for the reaction?


PLEASE HELP ME!

Respuesta :

LeChatNoir
K = ([H₂][I₂])/[HI]²
K = (0,01×0,01)/(0,8)²
K = 0,0001/0,64
K = 0,00015625

:•)
Eduard22sly

The equilibrium constant, K for the reaction given the data is 0.000156

Data obtained from the question

  • 2HI <=> H₂ + I₂
  • Concentration of HI = 0.8 M
  • Concentration of H₂ = 0.01 M
  • Concentration of I₂ = 0.01 M
  • Equilibrium constant (K) =?

How to determine the equilibrium constant

The equilibrium constant, K can be obtained as illustrated below:

K = [H₂][I₂] / [HI]²

K = (0.01 × 0.01) / (0.8)²

K = 0.000156

Learn more about equilibrium constant:

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