There are 18 bulls and 45 cows on a ranch. If 4 more bulls and 4
more cows were added will the ratio of balls to cows remain the same? Justify your answer with a ratio table

Respuesta :

[tex]\bf \cfrac{bulls}{cows}\qquad \cfrac{18}{45}\implies \cfrac{2}{5} \\\\\\ \textit{now lets add 4 to each}\qquad \cfrac{bulls}{cows}\qquad \cfrac{18+4}{45+4}\implies \cfrac{22}{49}[/tex]

now, 22/49 is not simplifiable further, thus the ratio changed.

Answer:

No, it won't same.

Step-by-step explanation:

Given,

The number of bulls = 18,

And, the number of cows = 45,

So, the ratio of the bulls and cow = [tex]\frac{18}{45}[/tex] = [tex]\frac{2}{5}[/tex]

After comprising 4 more bulls and 4 more cows,

The new number of cows = 45 + 4 = 49,

While, the new number of bulls = 18 + 4 = 22,

Thus, the new ratio of bulls and cow = [tex]\frac{22}{49}[/tex]

Since,

[tex]\frac{22}{49}\neq \frac{2}{5}[/tex]

Hence, the ratio of bulls to cows will not remain the same.