Respuesta :
V = 24.0 mL + (35.2 g)(mL/10.5g) = I think i'm not all that sure but I think its this.
Answer : The volume of new water level in graduated cylinder is 23.85 mL.
Explanation :
To calculate volume of a silver metal, we use the equation:
[tex]\text{Density of silver metal}=\frac{\text{Mass of silver metal}}{\text{Volume of silver metal}}[/tex]
We are given:
Density of silver metal = 10.5 g/mL
Mass of silver metal = 35.2 g
Putting values in above equation, we get:
[tex]10.5g/mL=\frac{35.2g}{\text{Volume of silver metal}}\\\\\text{Volume of silver metal}=3.35mL[/tex]
Now we have to calculate the volume of new water level in graduated cylinder.
Volume of water in graduated cylinder = 20.5 mL
Volume of silver metal = 3.35 mL
Volume of new water level = Volume of water in graduated cylinder + Volume of silver metal
Volume of new water level = 20.5 mL + 3.35 mL
Volume of new water level = 23.85 mL
Therefore, the volume of new water level in graduated cylinder is 23.85 mL.