marcysydnor17
contestada

A video store manager observes that the number of videos sold seems to vary inversely as the price per video. If the store sells 510
videos per week when the price per video is $17.40
, how many does he expect to sell if he lowers the price to $16
? Round your answer to the nearest integer if necessary.

Respuesta :

Answer:

  • 555

Explanation :

using the formula for inverse proportion,

  • y = k/x

here,

  • y = no. of videos
  • x = price per video
  • k = constant of proportionality

thus,

  • 510 = k/17.40
  • k = 510*17.40
  • k = 8874

now, we can find the number of videos expected to be sold if the price get lowered to $16,

  • y = 8874/16
  • y ≈ 555

thus, the manager can expect to sell a rough amount of 555 videos by lowering the charge to $16.

msm555

Answer:

555 videos

Step-by-step explanation:

When the number of videos sold varies inversely with the price per video, we can express this relationship with the equation:

[tex] \Large\boxed{\boxed{ y = \dfrac{k}{x}}} [/tex]

where

  • y is the number of videos sold,
  • x is the price per video, and
  • k is the constant of variation.

Given that the store sells 510 videos per week when the price per video is $17.40.

Now

we can substitute these values to find k:

[tex] 510 = \dfrac{k}{17.40} [/tex]

Solving for k:

[tex] k = 510 \times 17.40 [/tex]

Now we can use k to find the number of videos sold when the price per video is $16:

[tex] y = \dfrac{k}{16} [/tex]

Substitute the value of k into the equation:

[tex] y = \dfrac{510 \times 17.40}{16} [/tex]

Now, calculate:

[tex] y = \dfrac{8874}{16} [/tex]

[tex] y = 554.625 [/tex]

[tex] y = 555 \textsf{( rounded to nearest integer)}[/tex]

Therefore, the manager can expect to sell approximately 555 videos if he lowers the price to $16.

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