Respuesta :
6,02×10²³ N --- 1 mol NH₃
X ------------------ 0,41 mol
X = 6,02×10²³ × 0,41
X = 2,4682×10²³ atoms N
X ------------------ 0,41 mol
X = 6,02×10²³ × 0,41
X = 2,4682×10²³ atoms N
Answer: The number of nitrogen atoms in given moles of ammonia are [tex]2.47\times 10^{23}[/tex]
Explanation:
We are given:
A chemical compound having formula [tex]NH_3[/tex]
Moles of ammonia = 0.410 moles
In 1 mole of ammonia, 1 mole of nitrogen atoms and 3 moles of hydrogen atoms are present.
According to mole concept:
1 mole of compound contains [tex]6.022\times 10^{23}[/tex] number of atoms
So, 0.410 moles of ammonia molecule will contain = [tex]0.410\times 1\times 6.022\times 10^{23}=2.47\times 10^{23}[/tex] number of nitrogen atoms.
Hence, the number of nitrogen atoms in given moles of ammonia are [tex]2.47\times 10^{23}[/tex]