We are given an arithmetic sequence with
First term, a₁ = 6
Second term, a₂ = 2
Therefore the common difference is d = -4.
The n-th term is
[tex]a_{n} = a_{1} + (n-1)d \\ a_{n} = 6 - 4(n-1), \, for \, n \ge 1 [/tex]
Answer:
[tex]a_{n} = 6 - 4(n-1);[/tex] all integers where n ≥ 1