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Steam, at 100°C, is passed into a container of negligible heat capacity, containing 20g of ice and 100g of water at 0°C, until the ice is completely melted. Determine the total mass of water in the container. [ Specific latent heat of steam = 2.3 ×10'Jg', Specific latent heat of ice = 3.4 x 10'Jg', Specific heat capacity of water = 4.2Jg 'k'] ​

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QueenMeaw

Answer:

Total mass of water is 120g

Explanation:

Heat absorbed by the ice to melt it:

Q_ice = 20g × (3.4 × 10^5 J/kg)

Q_ice = 6.8 × 10^6 J

Heat absorbed by the resulting water to raise its temperature to 100°C:

Q_water = (20g + 100g) × (4.2 J/g°C) × (100°C)

Q_water = 42 × 10^3 J

Since the heat absorbed by the ice to melt it is equal to the heat absorbed by the resulting water to raise its temperature, the total mass of water in the container is

20g + 100g = 120g.

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