Respuesta :
pOH = 14-pH = 14-12,25 = 1,75
pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-1,75
[OH-] = 0,01778 mol/dm³
[NaOH] = [OH-] = 0,01778M
:•)
pOH = -log[OH-]
[OH-] = 10^-pOH
[OH-] = 10^-1,75
[OH-] = 0,01778 mol/dm³
[NaOH] = [OH-] = 0,01778M
:•)
Answer: 0.018 M
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.
[tex]pH=-\log [H^+][/tex]
Given: pH= 12.25
[tex]pH+pOH=14[/tex]
[tex]pOH=14-12.25=1.75[/tex]
[tex]pOH=-log[OH^-][/tex]
[tex]1.75=-log[OH^-][/tex]
[tex][OH^-]=0.018M[/tex]
[tex]NaOH\rightarrow Na^++OH^-[/tex]
Thus as 1 mole of [tex]NaOH[/tex] gives 1 mole of [tex]OH^-[/tex] thus concentration of [tex]NaOH[/tex] will be 0.018M.