justin17683
contestada

What is the equation of a line passing through the point (a, b) and having a slope of b?

y = −bx − b(1 − a)
y = bx − b(a − 1)
y=1/bx+b(a-1)
y=-1/bx+b(1-a)

Respuesta :

Ilyes39
The answer is y=bx-b(a-1), because when x=a then y=b.
texaschic101
y - y1 = m(x - x1)....slope = b, points (a,b)

y - b = b(x - a)
y - b = bx - ba
y = bx - ba + b
y = bx - b(a - 1) <===

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