2 to the fifth power over 3 squared all raised to the fourth power
[tex] \left(\dfrac{2^5}{3^2}\right)^4=\dfrac{(2^5)^4}{(3^2)^4}=\dfrac{2^{5\cdot4}}{3^{2\cdot4}}=\dfrac{2^{20}}{3^8} [/tex]
Answer: 2 to the twentieth power over 3 to the eighth power
Used:
[tex] \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a^n)^m=a^{n\cdot m} [/tex]
