Answer:
5 15/19 ≈ 5.79 mph
Step-by-step explanation:
You want Arjun's speed in still water if he traveled 37 miles with the 2 mph current in the same time it would take him to travel 18 miles against the current.
The relationship between time, speed, and distance is ...
t = d/s
Since the two times are the same, we have ...
[tex]\dfrac{37}{x+2}=\dfrac{18}{x-2}[/tex]
where x represents Arjun's speed in still water.
Multiplying the equation by (x+2)(x-2) gives ...
37(x -2) = 18(x +2)
37x -74 = 18x +36 . . . . eliminate parentheses
19x = 110 . . . . . . . . . . . . add 74 -18x
x = 110/19 = 5 15/19 ≈ 5.79 . . . . mph
Arjun's speed in still water is 5 15/19 mph, about 5.79 mph.
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Additional comment
The travel time in each direction is 4.75 hours.
