A roof rises 4 feet over a horizontal distance of 6 feet. What is the approximate angle formed by the horizontal and the roof?

Find the formula/concept used for this question ​

A roof rises 4 feet over a horizontal distance of 6 feet What is the approximate angle formed by the horizontal and the roof Find the formulaconcept used for th class=

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Answer:

approximately 34°

Step-by-step explanation:

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msm555

Answer:

33.7°

Step-by-step explanation:

To find the approximate angle formed by the horizontal and the roof, we can use basic trigonometry.

Given:

  • Opposite: 4 feet
  • Adjacent: 6 feet

Using the tangent function, which is defined as the ratio of the opposite side to the adjacent side in a right triangle, we have:

[tex] \tan(\theta) = \dfrac{\textsf{Opposite}}{\textsf{Adjacent}} [/tex]

[tex] \tan(\theta) = \dfrac{4}{6} [/tex]

[tex] \tan(\theta) = \dfrac{2}{3} [/tex]

Now, we can find the angle [tex] \theta [/tex] by taking the inverse tangent of this ratio:

[tex] \theta = \tan^{-1} \left(\dfrac{2}{3}\right) [/tex]

Using a calculator, we can find the approximate value of [tex] \theta [/tex].

[tex] \theta \approx 33.690067525979 [/tex]

[tex] \theta \approx 33.7 \textsf{ feet (in nearest tenth)}[/tex]

So, the approximate angle formed by the horizontal and the roof is [tex] \approx 33.7^\circ [/tex].

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