Respuesta :
To find the position of the center of mass relative to the center of Puck 1, we'll use the formula for the center of mass of a two-particle system:
\[ x_{\text{CM}} = \frac{m_1 \cdot x_1 + m_2 \cdot x_2}{m_1 + m_2} \]
where:
- \( x_{\text{CM}} \) is the position of the center of mass,
- \( m_1 \) and \( m_2 \) are the masses of Puck 1 and Puck 2, respectively, and
- \( x_1 \) and \( x_2 \) are the positions of Puck 1 and Puck 2, respectively, along the x-axis.
Given:
- \( m_1 = 146 \) g = 0.146 kg (convert to kilograms),
- \( m_2 = 48 \) g = 0.048 kg (convert to kilograms),
- \( x_1 = 0 \) (center of Puck 1, relative to itself),
- \( x_2 = 20 \) cm = 0.20 m (distance between the centers of the pucks).
Now, we plug these values into the formula:
\[ x_{\text{CM}} = \frac{(0.146 \, \text{kg} \cdot 0) + (0.048 \, \text{kg} \cdot 0.20 \, \text{m})}{0.146 \, \text{kg} + 0.048 \, \text{kg}} \]
\[ x_{\text{CM}} = \frac{0 + 0.0096 \, \text{m}}{0.194 \, \text{kg}} \]
\[ x_{\text{CM}} = \frac{0.0096 \, \text{m}}{0.194 \, \text{kg}} \]
\[ x_{\text{CM}} \approx 0.049 \, \text{m} \]
So, the center of mass is located approximately 0.049 meters to the right of the center of Puck 1.
Brainlist please
\[ x_{\text{CM}} = \frac{m_1 \cdot x_1 + m_2 \cdot x_2}{m_1 + m_2} \]
where:
- \( x_{\text{CM}} \) is the position of the center of mass,
- \( m_1 \) and \( m_2 \) are the masses of Puck 1 and Puck 2, respectively, and
- \( x_1 \) and \( x_2 \) are the positions of Puck 1 and Puck 2, respectively, along the x-axis.
Given:
- \( m_1 = 146 \) g = 0.146 kg (convert to kilograms),
- \( m_2 = 48 \) g = 0.048 kg (convert to kilograms),
- \( x_1 = 0 \) (center of Puck 1, relative to itself),
- \( x_2 = 20 \) cm = 0.20 m (distance between the centers of the pucks).
Now, we plug these values into the formula:
\[ x_{\text{CM}} = \frac{(0.146 \, \text{kg} \cdot 0) + (0.048 \, \text{kg} \cdot 0.20 \, \text{m})}{0.146 \, \text{kg} + 0.048 \, \text{kg}} \]
\[ x_{\text{CM}} = \frac{0 + 0.0096 \, \text{m}}{0.194 \, \text{kg}} \]
\[ x_{\text{CM}} = \frac{0.0096 \, \text{m}}{0.194 \, \text{kg}} \]
\[ x_{\text{CM}} \approx 0.049 \, \text{m} \]
So, the center of mass is located approximately 0.049 meters to the right of the center of Puck 1.
Brainlist please
