At a certain factory, weekly wages (w) are normally
distributed with a mean of $400 and a standard
deviation of $50. Find the probability that a worker
selected at random makes between $400 and $550.
-99.7%-
-95%-
-68%-
250 300 350 400 450 500 550
P(400 Be sure to use the 68% - 95% -99.7% rule and do not round.
Enter

Respuesta :

Answer:

Step-by-step explanation:

To find the probability that a worker selected at random makes between $400 and $550, we need to calculate the z-scores for both values and then use the z-table to find the probabilities.

Given:

Mean (μ) = $400

Standard deviation (σ) = $50

Calculate the z-scores for $400 and $550: For $400: [ z = \frac{X - \mu}{\sigma} = \frac{400 - 400}{50} = 0 ]

For $550: [ z = \frac{X - \mu}{\sigma} = \frac{550 - 400}{50} = 3 ]

Using the 68% - 95% - 99.7% rule:

The area between the mean and one standard deviation (z = 1) is approximately 68%.

The area between the mean and two standard deviations (z = 2) is approximately 95%.

The area between the mean and three standard deviations (z = 3) is approximately 99.7%.

Calculate the probability that a worker's wage is between $400 and $550:

Since $550 corresponds to z = 3, the area to the left of z = 3 is approximately 99.7%.

Since $400 corresponds to z = 0, the area to the left of z = 0 is 0.5 (50%).

Therefore, the probability that a worker makes between $400 and $550 is: [ P(400 < w < 550) = P(z < 3) - P(z < 0) = 0.997 - 0.5 = 0.497 ]

Therefore, the probability that a worker selected at random makes between $400 and $550 is approximately 49.7%.