HELP PLEASE, 90 POINTS!!! I'M DESPERATE

Given the circle below with chords GH and IJ.
Find the length of HK. Round to the nearest tenth if necessary.

HELP PLEASE 90 POINTS IM DESPERATEGiven the circle below with chords GH and IJ Find the length of HK Round to the nearest tenth if necessary class=

Respuesta :

Answer :

  • HK = 13.6

Explanation :

The intersecting chords theorem states that the product of the lengths of the line segments on each chord are equal.

thus,

  • GK*HK= JK*KI
  • 34*HK= 22*21
  • HK = 462/34
  • HK = 13.6

Answer:

HK = 13.6

Step-by-step explanation:

The given diagram shows a circle with two intersecting chords.

According to the Intersecting Chords Theorem, when two chords intersect inside a circle, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

Therefore, in this case:

[tex]\sf HK \times KG = IK \times KJ[/tex]

Given that KG = 34, I = 21 and KJ = 22, then:

[tex]\sf HK \times 34 = 21 \times 22[/tex]

Solver for HK:

[tex]\sf HK=\dfrac{21 \times 22}{34}\\\\\\HK=\dfrac{462}{34}\\\\\\HK=13.5882352941...\\\\\\HK=13.6\; (nearest\;tenth)[/tex]

Therefore, the length of segment HK rounded to the nearest tenth is:

[tex]\Large\boxed{\boxed{\sf HK=13.6}}[/tex]