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The angular speed of a rotating platform changes from ω0 = 2.8 rad/s to ω = 8.2 rad/s at a constant rate as the platform moves through an angle Δθ = 5.5 radians. The platform has a radius of R = 12 cm.

ω0 = 2.8 rad/s
ω = 8.2 rad/s
Δθ = 5.5 radians
R = 12 cm

Calculate the final centripetal acceleration ac, in m/s2, of a point at the outer edge of the platform .

Respuesta :

MathPhys

Answer:

560 m/s²

Explanation:

Centripetal acceleration is equal to the square of the tangential speed divided by the radius. The tangential speed is equal to the angular speed times the radius.

ac = v² / r

ac = (ωr)² / r

ac = ω² r

Plug in values.

ac = (8.2 rad/s)² / (0.12 m)

ac = 560 m/s²

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