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A ball is thrown downward from the top of a 200​-foot building with an initial velocity of 24 feet per second. The height of the ball h in feet after t seconds is given by the equation h equals negative 16t^2-24t+200. How long after the ball is thrown will it strike the​ ground? please fast

Respuesta :

Answer:

Step-by-step explanation:

Height, h, will equal zero when the ball hits the ground .

 Sooooo   0 = - 16t^2-24t + 200  

           Use quadratic formula   with a = - 16    b = -24    c = 200

                  to find t = 2.86 seconds

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