Answer:
Step-by-step explanation:
Given that a substance decays exponentially at the rate of k times the population present.
k = 0.00011
Q0 is the initial population, and Q(t) is the population at time t.
Relationship is given by
[tex]Q(t) = Q_{0} e^{-kt} =Q_{0} e^{-0.00011t}[/tex]
Let after t years there is half life
Then 1/2 =[tex]e^{-0.00011t}[/tex]
Take log
t = -ln2 /(-0.00011) = 6301.34 years