contestada

Fe2O3 + H2 --> Fe + H2O
A) what mass of hydrogen gas must be consumed to produe 10.0 g of iron metal?

B) what mass of iron(lll) oxide, Fe2O3, must be consumed to prepare 2.50g of iron metal

Respuesta :

Hippalectryon
A) 10.0g of Iron is [tex]\frac{10.0}{55.8}=179mmol[/tex] of Iron.

One mole of dihydrogen is required to form one mole of iron, hence you'll need [tex]0.179*1.00=0.179g[/tex] of dihydrogen.

B) Likewise : 2.50g of Iron is [tex]\frac{2.50}{55.8}=44.8mmol[/tex] of Iron, hence we'll need [tex]44.8*(3*16+2*55.8)=7.15g[/tex] of Fe2O3.

Otras preguntas