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Could someone please explain to me clearly how to work this out using quadratics?

Find the values of a, b, c, d and e that make this following equation true.
4[tex] x^{2}[/tex](x-2)(x+3)+3 = ax[tex] x^{4}[/tex]+b[tex] x^{3} [/tex]+c[tex] x^{2} [/tex]+dx+e

Respuesta :

konrad509
[tex]4x^2(x-2)(x+3)+3=ax^4+bx^3+cx^2+dx+e\\ 4x^2(x^2+3x-2x-6)+3=ax^4+bx^3+cx^2+dx+e\\ 4x^2(x^2+x-6)+3=ax^4+bx^3+cx^2+dx+e\\ 4x^4+4x^3-24x^2+3=ax^4+bx^3+cx^2+dx+e\\\\ a=4\\ b=4\\ c=-24\\ d=0\\ e=3[/tex]

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