Respuesta :
(ab+3)(ab−3)
=(ab+3)(ab+−3)
=(ab)(ab)+(ab)(−3)+(3)(ab)+(3)(−3)
=a^2b^2−3ab+3ab−9
=a^2b^2−9
=(ab+3)(ab+−3)
=(ab)(ab)+(ab)(−3)+(3)(ab)+(3)(−3)
=a^2b^2−3ab+3ab−9
=a^2b^2−9
Answer:
Option (c) is correct.
[tex]\left(ab\:+\:3\right)\left(ab\:-\:3\right)=a^2b^2-9[/tex]
Step-by-step explanation:
Given : [tex]\left(ab\:+\:3\right)\left(ab\:-\:3\right)[/tex]
We have to find the product of [tex]\left(ab\:+\:3\right)\left(ab\:-\:3\right)[/tex]
Consider the given expression [tex]\left(ab\:+\:3\right)\left(ab\:-\:3\right)[/tex]
Apply algebraic identity, [tex]\left(a+b\right)\left(a-b\right)=a^2-b^2[/tex]
We have,
a = ab and b = 3
[tex]=\left(ab\right)^2-3^2[/tex]
Simplify, we have,
[tex]=a^2b^2-9[/tex]
Thus, [tex]\left(ab\:+\:3\right)\left(ab\:-\:3\right)=a^2b^2-9[/tex]
