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An electric field is established by applying a potential difference to the plates. it is found that a field of strength e0 will cause the droplet to be suspended motionless. write an expression for the droplet's charge q. let g be the acceleration due to gravity.

Respuesta :

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When the particle is suspended motionless its weight is in equilibrium with the force applied on through the electric field. Thus 
[tex]mg=qE[/tex]
From this equality we can deduce the charge of the droplet necessary for the particle to stay suspended:
[tex]q= mg/E[/tex]
where m is its mass and E is the electric field that is applied.