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If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? note: power is defi ned as the product of voltage and current

Respuesta :

Let
I₁ = initial current, A
V₁ = initial voltage, V

The power is
P₁ = I₁*V₁  W

If P is reduced by 10% and the current is kept the same, then 
P₂ = 0.9P₁
I₂ = I₁

The new voltage, V₂, is given by
P₂ = I₂V₂
0.9P₁ = I₁V₂
0.9I₁V₁ = I₁V₂
V₂ = 0.9V₁

Answer: The voltage should be reduced by 10%

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