contestada

The temperature of a lead fishing weight rises from 26∘c to 38∘c as it absorbs 11.3 j of heat. what is the mass of the fishing weight in grams? (the specific heat capacity of lead is 0.128 j/g∘c.) express your answer in grams to two significant figures.

Respuesta :

Given:
ΔT = 38 - 26 = 12°C, temperature change
Q = 11.3 J, heat input
c = 0.128 J/(g-°C), specific heat of lead

Let m =  the mass of the lead.
Then
Q = m*c*ΔT
(m g)*(0.128 J/(g-°C))*(12 °C) = 11.3 J
1.536m = 11.3
m = 7.357 g

Answer:  7.36 g  (2 sig. figs)

Otras preguntas