Respuesta :
Iodine is in the seventh group and therefore has seven valence electrons. So it has seven dots. Because it wants to achieve a stable octet configuration (it wants eight electrons), two iodine atoms share a pair of valence electrons to form an I-I single covalent bond.
Dot structure is a representation of the valence electrons of an atom using the dots around the symbol of the atom. The dot structure of the iodine show 7 electrons.
Lewis Dot structure:
It is the representation of the valence electrons of an atom using the dots around the symbol of the atom.
The atomic number of the Iodine is 53
The electronic configuration,
[tex]\bold{ I_5_3 - 1s^22s^22p^63s^23p^64s^23d^1^04p^65s^24d^1^05p^5}[/tex]
The valence shell of the iodine is the 5th shell which contains 7 electrons.
Therefore, the dot structure of the iodine show 7 electrons.
To know more about dot structure, refer to the link:
https://brainly.com/question/20300458
