Respuesta :
Mg + 2HCl --> MgCl2 + H2
From the balanced equation , 2 moles of HCl produces 1 mole MgCl2
Therefore 3.38 moles of Hcl will produce
1/2 × 3.38 = 1.69
Mass = Moles × Mr of MgCl2
= 1.69 × ( 24 + ( 35.5 x 2) )
= 1.69 x 95
= 160.55 g
From the balanced equation , 2 moles of HCl produces 1 mole MgCl2
Therefore 3.38 moles of Hcl will produce
1/2 × 3.38 = 1.69
Mass = Moles × Mr of MgCl2
= 1.69 × ( 24 + ( 35.5 x 2) )
= 1.69 x 95
= 160.55 g
Answer: The mass of magnesium chloride produced in the given reaction is 16.09 grams.
Explanation:
We are given:
Moles of magnesium = 3.38 mol
Moles of hydrochloric acid = 3.38 mol
The chemical equation for the reaction of magnesium and hydrochloric acid follows:
[tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]
By Stoichiometry of the reaction:
2 moles of hydrochloric acid reacts with 1 mole of magnesium.
So, 3.38 moles of hydrochloric acid will react with = [tex]\frac{1}{2}\times 3.38=1.69mol[/tex] of magnesium.
As, given amount of magnesium is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of hydrochloric acid is producing 1 mole of magnesium chloride.
So, 3.38 moles of hydrochloric acid will react with = [tex]\frac{1}{2}\times 3.38=0.169moles[/tex] of magnesium chloride.
Now, calculating the mass of magnesium chloride by using equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of magnesium chloride = 95.21 g/mol
Moles of magnesium chloride = 0.169 moles
Putting values in above equation, we get:
[tex]0.169mol=\frac{\text{Mass of magnesium chloride}}{95.21g/mol}\\\\\text{Mass of magnesium chloride}=16.09g[/tex]
Hence, the mass of magnesium chloride produced in the given reaction is 16.09 grams.
