The formula for energy or enthalpy is:
E = m Cp (T2 – T1)
where E is energy = 63 J, m is mass = 8 g, Cp is the specific heat, T is temperature
63 J = 8 g * Cp * (340 K – 314 K)
Cp = 0.3 J / g K
Answer : The specific heat of substance is 0.30 J/g.K
Explanation :
Formula used :
[tex]Q=m\times c\times \Delta T[/tex]
or,
[tex]Q=m\times c\times (T_2-T_1)[/tex]
where,
Q = heat = 63 J
m = mass of substance = 8.0 g
[tex]C_w[/tex] = specific heat of substance = ?
[tex]T_1[/tex] = initial temperature = 314 K
[tex]T_2[/tex] = final temperature = 340 K
Now put all the given value in the above formula, we get:
[tex]63J=8.0g\times c\times (340-314)K[/tex]
[tex]c=0.30J/g.K[/tex]
Therefore, the specific heat of substance is 0.30 J/g.K
