Respuesta :
[tex]2:5\\2x:5x\\2x+5x=7x\\\\7x = 161\\x=23\\\\5\times 23= \boxed {115} \leftarrow answer[/tex]
Let
x--------> number of minivans at the school parking
y-------> number of other types of vehicles at the school parking
we know that
[tex] \frac{x}{y} =\frac{2}{5} \\\\ 5x=2y [/tex]
[tex] y= 2.5x [/tex] -----> equation [tex] 1 [/tex]
[tex] x+y=161 [/tex] ------> equation [tex] 2 [/tex]
Substitute equation [tex] 1 [/tex] in equation [tex] 2 [/tex]
[tex] x+(2.5x)=161\\\\ 3.5x=161\\\\ x=\frac{161}{3.5}\\\\x= 46 [/tex]
[tex] y=2.5*46\\ y=115 [/tex]
therefore
The number of minivans at the school parking is equal to [tex] 46 [/tex]
The number of other types of vehicles at the school parking is equal to [tex] 115 [/tex]
the answer is
The number of vehicles that are not minivans is [tex] 115 [/tex]