What is the area of a rectangle with vertices at (−6, 3) , (−3, 6) , (1, 2) , and (−2, −1) ? Enter your answer in the box. Do not round any side lengths.

You would have to find the magnitude of the sides to find out the area.

A=(-6, 3)
B= (-3,6)
C= (1, 2)
D= (-2, -1)

A-B = √(x₁-x₂)²+(y₁-y₂)²
=√(-6+3)²+(3-6)²
=√9+9
=√18
=4.24

C-D=√(x₁-x₂)²+(y₁-y₂)²
=√(1+2)²+(2+1)²
=√9+9
=4.24

Area= lxw
A=√18x√18
a=18

Hope I helped :)

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krudd2000oxkx24 krudd2000oxkx24 · Answer 2 · 2018-11-22T04:45:55+01:00

krudd2000oxkx24 krudd2000oxkx24

22-11-2018

For those of you who's vertices read as (6,-3), (3,-6), (-1,-2), and (2,1) AKA the Opposite of this question, your answer is:

24

I took the test and that is what I got.

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What is the area of a rectangle with vertices at ​ (−6, 3) ​, ​ (−3, 6) ​ , (1, 2) , and (−2, −1) ? Enter your answer in the box. Do not round any side lengths.

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What is the area of a rectangle with vertices at (−6, 3) , (−3, 6) , (1, 2) , and (−2, −1) ? Enter your answer in the box. Do not round any side lengths.