using herons formula you find the area s=24/2=12 [tex] A=\sqrt{s(s-a)(s-b)(s-c)} [/tex] A=24 and A=0.5 base height sp 24=0.5 (base=AB=10)(height=c to the midpoint of segment AB) 24=5(height) [tex] \frac{24}{5} [/tex]=height
midpoint of AB is obviously 5 because its asking for half of the line . Then layout the triangle as shown in the diagram . then use Pythagoras theorem which is the hypotenuse squared is equal to the 2 shorter legs squared. c2=a2+b2 c2=5^2+6^2 c2=25+36 c2=61 c=square root of 61
