Respuesta :
using Δh = q+w
under adiabatic conditions q = 0
w= 25joules
Δh= 25joules
under adiabatic conditions q = 0
w= 25joules
Δh= 25joules
Answer:
The change in internal energy will be 25 J.
Explanation:
Given that,
Work done = 25 J
Using first law of thermodynamics
The internal energy is sum of the heat and work done.
[tex]\Delta U= Q+ W[/tex]
Where, [tex]\Delta U[/tex] = Change in internal energy
Q = heat
W = work done
In adiabatic process, the heat does not change, it remains constant.
So the heat Q = 0
Therefore, The change in internal energy will be
[tex]\Delta U=0+25 J[/tex]
[tex]\Delta U= 25 J[/tex]
Hence, The change in internal energy will be 25 J.