now, the integers are consecutive, one right after/before the next one.
so.. hmmm let's say our first one is "a".
if the first integer is "a", then the next one will be "a+1", one hop over.
and the last one will then be, another hop over, "(a+1)+1", or "a+2".
now, we know they add to 267, ok
[tex]\bf a+(a+1)+(a+2)=267\implies a+a+1+a+2=267
\\\\\\
3a=267-3\implies 3a=264\implies a=\cfrac{264}{3}\implies a=88[/tex]
and surely you'd know what the others are.
