Write a function rule for the area of a rectangle whose length is 6 ft more than its width. What is the area of the rectangle when its width is 12 ft?

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tranquynhyennhi tranquynhyennhi · Answer 1 · 2017-10-22T03:46:20+02:00

Let x be the width.
=> x+6 will be the length.
Function: x(x+6)= x^2+6x

Area= 12^2+6.12= 216 ft

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keshavgandhi04 keshavgandhi04 · Answer 2 · 2021-12-16T11:15:51+01:00

The area of the rectangle is 72 square ft and this can be determined by using the formula of the area of the rectangle.

Given :

Length is 6 ft more than its width.

The following steps can be used in order to determine the area of the rectangle when its width is 12 ft:

Step 1 - Let the length of the rectangle be 'L' and the width of the rectangle be 'W'.

Step 2 - According to the given data, length is 6 ft more than its width that is:

L = 6 + W

Step 3 - The formula of the area of the rectangle is given below:

A = LW

Step 4 - Substitute the value of 'L' in the above expression.

A = (6 + W)W

Step 5 - Now, at W = 6ft the area of the rectangle becomes:

A = (6 + 6)6

A = 72 square ft.

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