Write an equation of the line passing through point P (2,3) that is perpendicular to the time y-4=-2(x+3)

The equation of line which is perpendicular to the given line and has a given point is required.
The equation of the line is [tex]y=\dfrac{1}{2}x+2[/tex].
The given line is
[tex]y-4=-2(x+3)\\\Rightarrow y-4=-2x-6\\\Rightarrow y=-2x-2[/tex]
The slope of the given line is [tex]m_1=-2[/tex]
For a line to be perpendicular we have the condition
[tex]m_1m_2=-1\\\Rightarrow m_2=\dfrac{-1}{-2}\\\Rightarrow m_2=\dfrac{1}{2}[/tex]
The point is [tex]P(2,3)[/tex]
The equation will be
[tex]y=m_2x+c\\\Rightarrow 3=\dfrac{1}{2}\times 2+c\\\Rightarrow c=3-1=2[/tex]
[tex]y=\dfrac{1}{2}x+2[/tex]
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