meredithy99
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What additional information could you use to show that ΔSTU ≅ ΔVTU using SAS? Check all that apply.
UV = 14 ft and m∠TUV = 45°
TU = 26 ft
m∠STU = 37° and m∠VTU = 37°
ST = 20 ft, UV = 14 ft, and m∠UST = 98°
m∠UST = 98° and m ∠TUV = 45°

What additional information could you use to show that ΔSTU ΔVTU using SAS Check all that apply UV 14 ft and mTUV 45 TU 26 ft mSTU 37 and mVTU 37 ST 20 ft UV 14 class=

Respuesta :

I believe the correct answers are:

UV = 14 ft and m∠TUV = 45°
ST = 20 ft, UV = 14 ft, and m∠UST = 98°

Or, in other words, Options A and D.
aksnkj

Answer:

The information used are [tex]UV =14 \rm \; ft[/tex], [tex]\mathit TV=14 \rm \; ft[/tex], [tex]m\angle STU=37^{\circ}[/tex], and [tex]m\angle VTU=37^{\circ}[/tex].

Step-by-step explanation:

It is required to prove that triangle STU is congruent to the triangle VTU using SAS congruency rule.

SAS congruency rule is the side angle side rule, in which two sides should be equal and one angle between these two sides should also be equal.

Now, in triangle STU and triangle VTU,

[tex]ST=VT=14\rm \; ft\\m\angle STU=m\angle VTU=37^{\circ}\\TU=TU \texttt{ ; Common side}[/tex]

So, using SAS congruency rule, [tex]\Delta STU \cong \Delta VTU[/tex].

Therefore, the information used are [tex]UV =14 \rm \; ft[/tex], [tex]\mathit TV=14 \rm \; ft[/tex], [tex]m\angle STU=37^{\circ}[/tex], and [tex]m\angle VTU=37^{\circ}[/tex].

For more details, refer the link:

https://brainly.com/question/19883734?referrer=searchResults

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