Respuesta :
2x + 4 = 3(x - 2) + 1
2x + 4 = 3x - 6 + 1
2x + 4 = 3x - 5
2x - 3x = -5 - 4
-x = -9
x = 9
one solution
=================
4(x + 3) = 3x + 17
4x + 12 = 3x + 17
4x - 3x = 17 - 12
x = 5
one solution
================
3x + 4 + 2x = 5(x - 2) + 7
5x + 4 = 5x - 10 + 7
5x + 4 = 5x - 3
5x - 5x = -3 - 4
0 = -7
no solutions
===============
2(1 + 5x) = 5(2x - 1)
2 + 10x = 10x - 5
10x - 10x = -5 - 2
0 = -7
no solution
===============
-18 + 15x = 3(4x - 6) + 3x
-18 + 15x = 12x - 18 + 3x
-18 + 15x = 15x - 18
15x - 15x = -18 + 18
0 = 0
infinite solutions
===============
-10 + 5x = 5(x - 3) + 5
-10 + 5x = 5x - 15 + 5
-10 + 5x = 5x - 10
5x - 5x = -10 + 10
0 = 0
infinite solutions
===============
if the variables cancel out leaving u with an untrue statement, like 0 = 4 or 2 = 6, then u will have no solutions
if the variables cancel out leaving u with a true statement, like 2 = 2 or 4 = 4, then u will have infinite solutions
if u end up with a variable equaling a number, then u have 1 solution
==============
3x + 4 = 2x + 2
3x - 2x = 2 - 4
x = -2
one solution
=============
3(x + 2) + 1 = 3x + 7
3x + 6 + 1 = 3x + 7
3x + 7 = 3x + 7
3x - 3x = 7 - 7
0 = 0
infinite solutions
============
2x + 3 = 2x + 4 + 1
2x + 3 = 2x + 5
2x - 2x = 5 - 3
0 = 2
no solutions
2x + 4 = 3x - 6 + 1
2x + 4 = 3x - 5
2x - 3x = -5 - 4
-x = -9
x = 9
one solution
=================
4(x + 3) = 3x + 17
4x + 12 = 3x + 17
4x - 3x = 17 - 12
x = 5
one solution
================
3x + 4 + 2x = 5(x - 2) + 7
5x + 4 = 5x - 10 + 7
5x + 4 = 5x - 3
5x - 5x = -3 - 4
0 = -7
no solutions
===============
2(1 + 5x) = 5(2x - 1)
2 + 10x = 10x - 5
10x - 10x = -5 - 2
0 = -7
no solution
===============
-18 + 15x = 3(4x - 6) + 3x
-18 + 15x = 12x - 18 + 3x
-18 + 15x = 15x - 18
15x - 15x = -18 + 18
0 = 0
infinite solutions
===============
-10 + 5x = 5(x - 3) + 5
-10 + 5x = 5x - 15 + 5
-10 + 5x = 5x - 10
5x - 5x = -10 + 10
0 = 0
infinite solutions
===============
if the variables cancel out leaving u with an untrue statement, like 0 = 4 or 2 = 6, then u will have no solutions
if the variables cancel out leaving u with a true statement, like 2 = 2 or 4 = 4, then u will have infinite solutions
if u end up with a variable equaling a number, then u have 1 solution
==============
3x + 4 = 2x + 2
3x - 2x = 2 - 4
x = -2
one solution
=============
3(x + 2) + 1 = 3x + 7
3x + 6 + 1 = 3x + 7
3x + 7 = 3x + 7
3x - 3x = 7 - 7
0 = 0
infinite solutions
============
2x + 3 = 2x + 4 + 1
2x + 3 = 2x + 5
2x - 2x = 5 - 3
0 = 2
no solutions