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brookeenright

you split the problem into two separate problems and go from there.

so, (5x+15) and (xy+3y)  then you take out the common factor in both

so, positive 5 out of (5x+15) and positive y out of (xy+3y)

you'll then have 5(x+3) and y(x+3)

The x=3 is similar in both problems so you can combine them to make one and combine the two factors you took out to make another problem.

So your final answer is (x+3)(5+y)


altavistard
I saw right away that 5 is common to the left 2 terms and that y is common to the right 2 terms.  Thus, 5(x+3)+y(x+3)   =   (x+3)(5+y)

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