A 5.22-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.10 m/s and its y component of velocity is -2.82 m/s. (a) what is the kinetic energy of the object at this time?

Respuesta :

AL2006

The magnitude of the object's velocity is

         √ (5.1² + 2.82²)  =  √ (33.9624)  =  5.828 m/s .

Kinetic energy = (1/2) (M) (speed²)

                       =  (1/2) (5.22 kg) (5.828 m/s)²

                       =     (2.61 kg) (33.9624 m²/s²)

                       =          88.64    kg-m²/s²

                       =          88.64  Joules