An electric heater is constructed by applying a potential difference of 120 v to a nichrome wire that has a total resistance of 6.00 . find the current carried by the wire and the power rating of the heater.

Current = (voltage) / (resistance)

= (120 v) / (6 Ω) = 20 Amperes .

Electrical power = (voltage) x (current) .

= (120 v) x (20 Amperes)

= 2,400 watts .

That amount of power will sure toast your buns in a hurry.

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snehashish65 snehashish65 · Answer 2 · 2021-11-28T09:35:40+01:00

The current carried by the wire and the power rating of the heater are 20 A and 2400 W respectively.

Given data:

The potential difference across the electric heater is, V' = 120 V.

The total resistance of the nichrome wire is, [tex]R= 6.00 \;\rm \Omega[/tex].

First we need to apply the Ohm's law to find the current through the wire. The expression for the Ohm's law is given as,

[tex]V'= I \times R\\\\I =\dfrac{V'}{R}\\\\I =\dfrac{120}{6}\\\\I=20 \;\rm A[/tex]

Now, the expression for the electric power through the heater is given as,

[tex]P= V \times I\\\\P= 120 \times 20\\\\P =2400 \;\rm W[/tex]

Thus, we can conclude that the current carried by the wire and the power rating of the heater are 20 A and 2400 W respectively.

Learn more about the Ohm's law here:

https://brainly.com/question/10006666