Respuesta :
Assume you have 1 L of the material (you can assume any volume you want, you'll get the same answer).
Using the density, the one L has a mass of 1114 g
20% by mass of phosphoric acid means the mass of phosphoric acid is 0.20 * 1114 g
Calculate the moles of phosphoric acid
Molarity, M, mole / L = moles of acid / volume or 1 L
Using the density, the one L has a mass of 1114 g
20% by mass of phosphoric acid means the mass of phosphoric acid is 0.20 * 1114 g
Calculate the moles of phosphoric acid
Molarity, M, mole / L = moles of acid / volume or 1 L
Answer:
Molarity is 2.272M
Explanation:
The mass % of phosphoric acid is 20.0%
It means in 100 g of solution there is 20g of phosphoric acid in it.
Molarity = moles of solute dissolved per litre of solution.
So we need volume of solution
Volume can be calculated from mass and density as
Volume = mass / Density = 100/1.114 = 89.77 mL = 0.08977 L
Moles of solute = mass of solute / molar mass of solute
moles of solute = 20g / 98 = 0.204
molarity = [tex]\frac{moles}{volume}=\frac{0.204}{0.08977} =2.272M[/tex]