Respuesta :
The sum of the measures of the interior angles of a polygon of n sides is
180(n - 2)
If the polygon is regular, all angles are congruent, and each angle measures
[180(n - 2)]/n
Set the measure of one angle equal to 140, and solve for n, the number of sides.
[180(n - 2)]/n = 140
180(n - 2) = 140n
180n - 360 = 140n
40n = 360
n = 9
The number of sides is 9.
180(n - 2)
If the polygon is regular, all angles are congruent, and each angle measures
[180(n - 2)]/n
Set the measure of one angle equal to 140, and solve for n, the number of sides.
[180(n - 2)]/n = 140
180(n - 2) = 140n
180n - 360 = 140n
40n = 360
n = 9
The number of sides is 9.
The polygon has 9 sides.
[tex]\frac{360}{n}[/tex] = 40
360 = 40n
n = 9
180 - 140 = 40°
Therefore, the polygon has 9 sides.