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Is the line through points P(-8-10) and Q(-5,-12) perpendicular to the line through points R(9,-6) and S(17,-5)? Explain.

Respuesta :

Nadeshiko
Well let's find the slope of both coordinates first.

Slope = y2 - y1 / x2 - x1

1) Find the slope of PQ

Slope = -12 - (-10) / -5 - (-8)

Slope = -12 + 10 / -5 + 8

Slope = -2 / 3

Slope = - 2 / 3

The slope is negative two-thirds.

2) Find the slope of RS

Slope = -5 - (-6) / 17 - 9

Slope = -5 + 6 / 8

Slope = 1/8

The slope is one over eight

Solution: Since the slopes are not negative reciprocals of each other, they cannot be perpendicular.
Ver imagen Nadeshiko
Reeny15

Answer:

No, the line through points P(–8, –10) and Q(–5, –12) is not perpendicular to the line through points R(9, –6) and S(17, –5). Two lines are called perpendicular to each other if the product of their slope is -1.

Step-by-step explanation:

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