Assign an oxidation number to each element in the reaction.

CO(g) + 2H2(g) → CH3OH(g)

In CO, the oxidation number of C is _, and that of O is _.
In H2, the oxidation number of H is _.
In CH3OH, the oxidation number of C is _, that of O is _, and that of H is _.

The oxidation number of an atom in a compound is a charge that it appears to have as determined by some arbitrarily rules. The oxidation state of each atom in the compound are;

In CO - C has an oxidation number of +2
In H2 - H has an oxidation number of zero

In CH3OH - C has an oxidation number of -3, the oxidation number of O is -2 while the oxidation number of H is +1.

Hence, the oxidation number of atoms in a compound are determined by some arbitrary rules.

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Assign an oxidation number to each element in the reaction. CO(g) + 2H2(g) → CH3OH(g) In CO, the oxidation number of C is _, and that of O is _. In H2, the oxidation number of H is _. In CH3OH, the oxidation number of C is _, that of O is _, and that of H is _.

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Assign an oxidation number to each element in the reaction.

CO(g) + 2H2(g) → CH3OH(g)

In CO, the oxidation number of C is _, and that of O is _.
In H2, the oxidation number of H is _.
In CH3OH, the oxidation number of C is _, that of O is _, and that of H is _.