Answer:
The odds against winning the game is 3 to 1.
Step-by-step explanation:
*Probability states that it is the likelihood of something happening in the future.
*Its value lie between 0 and 1.
*complement of an event is that event that is not occurring .
Then, the probability of Event A will not occur is denoted by P(A').
Given:
The probability of winning a particular game at game place is [tex]\frac{1}{4}[/tex]
or we can write this as P(X) = [tex]\frac{1}{4}[/tex] where X is winning a particular game at game place.
To find the odds against winning the game:
P(X') = P(Not winning a game) = 1-P(X) = [tex]1-\frac{1}{4} = \frac{4-1}{4} =\frac{3}{4}[/tex]
Now, we have
the probability of winning is [tex]\frac{1}{4}[/tex] = 25%
and the probability of not winning is [tex]\frac{3}{4}[/tex] = 75%
Therefore, odds against winning is (chances against success) : (chances for success) = 3 to 1 or 3 : 1
