Respuesta :
the cashier has 16 $10 bills and 14 $20 bills
16×20=320
14×10=140
320+140=460
16×20=320
14×10=140
320+140=460
Answer:
There are 14 $10 bills and 16 $20 bills.
Step-by-step explanation:
Let
x = number of $10 bills
y = number of $20 bills
The sum of the value of x and y is $460.
10 x + 20 y = 460 [1]
The sum of x and y is equal to the total number of bills.
x + y = 30
y = 30 - x [2]
We replace [2] in [1],
10 x + 20 (30 - x) = 460
10 x + 600 - 20 x = 460
-10 x = -140
x = 14
We can get y if we replace this value of x in [2].
y = 30 - 14 = 16