Respuesta :
Answer:
We are given a inequality as:
[tex]y\leq -x^2+2x[/tex]
- We know that the graph of this inequality will be a solid parabola ( since the inequality is with equality sign) .
- The parabola will be downward parabola ( Since for any general equation of parabola as y=ax^2+bx+c if a<0 then the parabola is downward and if a>0 then the parabola is upward)
- Also the roots of the parabola are the points where y=0.
( The roots are: -x(x-2)=0
x=0 and x=2 are the roots of the parabola)
- Also the region inside the parabola is shaded.
(This could be checked by taking different points)

Inequalities are used to represent unequal expressions.
The solution to the inequality is: [tex]\mathbf{(x,y) \ge \{(0,0),(-2,-4)\}}[/tex]
The inequality is given as:
[tex]\mathbf{y \le - x^2 + 2x}[/tex]
The first step is to split the inequality as follows:
[tex]\mathbf{y \le - x^2}[/tex]
[tex]\mathbf{y \le 2x}[/tex]
Next, plot the graphs of the inequalities
i.e. the graphs of [tex]\mathbf{y \le - x^2}[/tex] and [tex]\mathbf{y \le 2x}[/tex] (see attachment for the graph)
Lastly, select the point or points of intersection of the graphs of [tex]\mathbf{y \le - x^2}[/tex] and [tex]\mathbf{y \le 2x}[/tex]
From the attached graph, the points of intersection of [tex]\mathbf{y \le - x^2}[/tex] and [tex]\mathbf{y \le 2x}[/tex] are:
[tex]\mathbf{(x,y) = \{(0,0),(-2,-4)\}}[/tex]
Hence, the solution to the inequality is:
[tex]\mathbf{(x,y) \ge \{(0,0),(-2,-4)\}}[/tex]
Read more about graphs of inequalities at:
https://brainly.com/question/15748955
