Depends on the question...
If your question is 2/3b + 5 = 7, then follow this one
[tex]\frac{2}{3}b + 5 = 7\\\\\sf You~ first~subtract~ 5 ~on ~both~ sides\\\\Then ~you~multiply~by~\frac{3}{2}~on~both~sides.\\\\ So...\\\\ \frac{2}{3}b + 5 - 5 = 7 - 5\\\\\frac{2}{3}b = 2\\\\\frac{2}{3}b \times \frac{3}{2} = 2 \times \frac{3}{2}\\\\b = 3[/tex]
Your final answer will be b = 3
If your question is 2/3b - 5 = 7, then follow this one
[tex]\frac{2}{3}b - 5 = 7\\\\\sf You~ first~add~ 5 ~on ~both~ sides\\\\Then ~you~multiply~by~\frac{3}{2}~on~both~sides.\\\\ So...\\\\ \frac{2}{3}b - 5 + 5 = 7+5 \\\\\frac{2}{3}b = 12\\\\\frac{2}{3}b \times \frac{3}{2} = 12 \times \frac{3}{2}\\\\b =18[/tex]
Your final answer will be b = 18
